TheNiceLife.com Blog: Algebra 101 : Why The Washington Redskins Are The True Superbowl Champions

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TheNiceLife.com Blog: Algebra 101 : Why The Washington Redskins Are The True Superbowl Champions

Algebra 101 : Why The Washington Redskins Are The True Superbowl Champions

Pure mathematics is, in its way, the poetry of logical ideas. ~ Albert Einstein

Math is beautiful. You just can't argue with numbers. 1 + 1 will always equal 2.

Nearly one month ago, on January 9th, I predicted a Giants Superbowl victory (see my Twitter page for proof), and created the algebraic truth that I'm about to reveal today. Last night, that prophecy came true as the New York Giants defeated the New England Patriots to win Superbowl 46.

I was privileged to watch the Giants play on opening day this year, as they battled my beloved Washington Redskins on the 10th anniversary of the September 11th terrorist attacks.

The Redskins crushed the Giants 28 - 14.

Fast forward to Week 15, the Redskins traveled to New York to face the Giants on their own turf. The Skins, once again, crushed the Giants by a score of 23 - 10, thereby, proving themselves to be the superior team.

Now let's enjoy my potent algebra equation.

If A is greater than B and B equals C, then A must also be greater than C.

A > B = C

A > C

Now we'll plug in the variables.

A = The Washington Redskins

B = The New York Giants

C = Superbowl Champions

Which now looks like this: The Washington Redskins [A] proved themselves to be greater than The New York Giants [B] who now call themselves Superbowl Champions [C]. Since B = C, and we understand that A is greater than B, we must rightfully assume that A (The Washington Redskins) are the TRUE Superbowl Champions.

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